Question

498+(2,7-5x)(6x-7)=(9-0,5x)(60x+1)

Answer 1

498+16.2x-18.9-30x2-35x=540x+9-30x2-0.5x

498+16.2x-18.9+35x=540x+9-0.5x

479.1=51.2x=539.5+9

51.2x-539.5x=9-479.1

-488.3x=-470.1

x=4701/4883

x приблизительно 0.962728

Answer 2

Let's start by expanding the terms on both sides of the equation:

498 + (2.7 - 5x)(6x - 7) = (9 - 0.5x)(60x + 1)

Expanding the left-hand side:

498 + (2.7 - 5x)(6x - 7) = 498 + 16.2x - 23.1x - 35.7 = -35.7 - 6.9x

Expanding the right-hand side:

(9 - 0.5x)(60x + 1) = 540x + 9 - 30x - 0.5x^2 = -0.5x^2 + 510x + 9

Now we can substitute these expressions back into the original equation:

-35.7 - 6.9x = -0.5x^2 + 510x + 9

Moving all the terms to one side:

0.5x^2 - 516.9x - 44.7 = 0

We can solve for x using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 0.5, b = -516.9, and c = -44.7

x = (-(-516.9) ± sqrt((-516.9)^2 - 4(0.5)(-44.7))) / 2(0.5) x = (516.9 ± sqrt(267082.41 + 44.7)) / 1 x = (516.9 ± sqrt(267127.11)) / 1 x ≈ 1018.675 or x ≈ -2.775

Therefore, the solutions to the equation are x ≈ 1018.675 and x ≈ -2.775.