Question

Log 2 (6x-3) =log (3x+1)

Answer 1

6x-3=3x+1
6x-3x=1+3
3x=4
x=4/3
x=1, 3

Answer 2

To solve the equation:

log2(6x-3) = log(3x+1)

We can use the following logarithmic identity:

loga(b) = logc(b) / logc(a)

Using this identity, we can rewrite the left-hand side of the equation:

log2(6x-3) = log(3x+1) / log2

Now we can equate the two logarithms and solve for x:

log(6x-3)/log2 = log(3x+1)/log2

log(6x-3) = log(3x+1)

6x - 3 = 3x + 1

3x = 4

x = 4/3

Therefore, the solution to the equation is x = 4/3.