Question

(8x-1)(8x+1)-(16x-3)(4x+1)

Answer 1

(8x-1)(8x+1)-(16x-3)(4x+1)=64x^2-1-(64x^2+16x-12x-3)= 64x^2-1-64x^2-16x+12x+3=28x+2

Answer 2

To simplify the expression (8x-1)(8x+1) - (16x-3)(4x+1), we can use the distributive property and perform the necessary multiplication:

(8x-1)(8x+1) - (16x-3)(4x+1)

Expanding the first parentheses: (64x^2 - 1) - (16x-3)(4x+1)

Now, let's expand the second parentheses using the distributive property: (64x^2 - 1) - (64x^2 + 16x - 12x - 3)

Simplifying inside the parentheses: 64x^2 - 1 - (64x^2 + 4x - 3)

Distribute the negative sign to the terms inside the second parentheses: 64x^2 - 1 - 64x^2 - 4x + 3

Combining like terms: (64x^2 - 64x^2) + (-4x) + (3 - 1)

The terms with the same degree cancel each other out: 0x^2 - 4x + 2

Simplifying further: -4x + 2

Therefore, the simplified form of the expression (8x-1)(8x+1) - (16x-3)(4x+1) is -4x + 2.