Question

1) 5^3*7^5:35^4=, 2)(7*4^-2)(44*5^-4)=, УМОЛЯЮ ПОМОГИТЕ

Answer 1

1) 5^3*7^5:35^4=125*16807:1500625=1.4
2)(7*4^-2)(44*5^-4)=(7*0.0625)(44*0.016)=0.4375*0.704=0.308

Answer 2

1. To solve this problem, we can simplify both sides of the equation first. We have:

5^3 * 7^5 = (555) * (77777) 35^4 = (57)^(24) = 5^8 * 7^8

Therefore, the equation can be written as:

(555) * (77777) / (5^8 * 7^8) = (57)^(24)

Simplifying further, we have:

(5^2 * 7^4) / (5^8 * 7^8) = 5^8 * 7^2

Now, we can cancel out common factors of 5 and 7 on both sides of the equation:

1 / (5^6 * 7^4) = 5^8 * 7^2

Multiplying both sides by 5^6 * 7^4, we get:

1 = 5^14 * 7^6

Therefore, the solution to the equation is:

5^3 * 7^5 / 35^4 = 1 / (5^6 * 7^4) = 5^(-14) * 7^(-6)

2. To simplify this expression, we can multiply the terms inside the parentheses first:

(74^-2)(445^-4) = (7/16) * (44/625)

Now, we can simplify this further by finding a common factor of 7 and 44, and a common factor of 16 and 625:

(7/16) * (44/625) = (711) / (1625) = 77/400

Therefore, the solution to the expression is:

(74^-2)(445^-4) = 77/400.