Question

A)(x+3y)² Б)(7-x)(7+x) В)(3а+2b)(3a-2b)

Answer 1

А)х^2+6ху+9у^2
б)49-4^2
в)9а^2-4б^2

Answer 2

A)

To expand the expression (x+3y)², we can use the formula (a+b)² = a² + 2ab + b², where a = x and b = 3y.

So, we have:

(x+3y)² = x² + 2(x)(3y) + (3y)² = x² + 6xy + 9y²

Therefore, the expanded form of (x+3y)² is x² + 6xy + 9y².

B)

To expand the expression (7-x)(7+x), we can use the formula (a-b)(a+b) = a² - b², where a = 7 and b = x.

So, we have:

(7-x)(7+x) = 7² - x² = 49 - x²

Therefore, the expanded form of (7-x)(7+x) is 49 - x².

C)

To expand the expression (3a+2b)(3a-2b), we can use the formula (a+b)(a-b) = a² - b², where a = 3a and b = 2b.

So, we have:

(3a+2b)(3a-2b) = (3a)² - (2b)² = 9a² - 4b²

Therefore, the expanded form of (3a+2b)(3a-2b) is 9a² - 4b².