
X-5x+6=0 x-8x+7=0 x-9x+8=0


Ответы на вопрос

х = 6/4 = 3/2 = 1 1/2
2) - 7х = - 7
х = 1
3) - 8х = - 8
х = 1



Ответ:
1) x_1= 3; x_2= 2;
2) x_1= 7; x_2= 1;
3) x_1= 8; x_2= 1.



To solve each of these equations, we can use the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Let's solve each equation step by step:
x - 5x + 6 = 0 Rearranging the terms, we get: -4x + 6 = 0 Comparing this equation to the general form ax^2 + bx + c = 0, we have a = -4, b = 0, and c = 6. Substituting these values into the quadratic formula: x = (-0 ± √(0^2 - 4(-4)(6))) / (2(-4)) x = (± √(0 - (-96))) / (-8) x = (± √96) / (-8) Simplifying further, we have: x = ± √(96) / (-8) x = ± √(16 * 6) / (-8) x = ± (4√6) / (-8) Simplifying the fraction, we get: x = ± (√6) / (-2) So the solutions are: x = -√6 / 2 and x = √6 / -2, or simply x = -√6 / 2 and x = √6 / 2.
x - 8x + 7 = 0 Rearranging the terms, we get: -7x + 7 = 0 Comparing this equation to the general form ax^2 + bx + c = 0, we have a = -7, b = 0, and c = 7. Substituting these values into the quadratic formula: x = (-0 ± √(0^2 - 4(-7)(7))) / (2(-7)) x = (± √(0 - (-196))) / (-14) x = (± √(196)) / (-14) Simplifying further, we have: x = ± (14) / (-14) x = ± 1 So the solutions are: x = -1 and x = 1.
x - 9x + 8 = 0 Rearranging the terms, we get: -8x + 8 = 0 Comparing this equation to the general form ax^2 + bx + c = 0, we have a = -8, b = 0, and c = 8. Substituting these values into the quadratic formula: x = (-0 ± √(0^2 - 4(-8)(8))) / (2(-8)) x = (± √(0 - (-256))) / (-16) x = (± √(256)) / (-16) Simplifying further, we have: x = ± (16) / (-16) x = ± 1 So the solutions are: x = -1 and x = 1.
Therefore, the solutions to the given equations are as follows:
Equation 1: x = -√6 / 2 and x = √6 / 2 Equation 2: x = -1 and x = 1 Equation 3: x = -1 and x = 1


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