Question

(6y+2)(5-y)=47-(2y-3)(3y-1)

Answer 1

 (6y + 2)(5 – y) = 47 – (2y – 3)(3y – 1), 30y – 6y2 + 10 – 2y = 47 – 6y2 + 2y + 9y – 3, 28 – 6y2 + 6y2 – 11y = 47 – 3 – 10,   17y = 34,   y = 2.

Answer 2

30y-6y"+10-2y=47-6y"+2y+9y-330y-6y"+10-2y-47+6y"-2y-9y+321y-34=021y=34 y=1целая 13 дробная черта 21  
только в столбик...

Answer 3

Let's solve the given equation step by step.

Expanding both sides of the equation:

(6y + 2)(5 - y) = 47 - (2y - 3)(3y - 1)

First, let's expand the left side of the equation:

(6y + 2)(5 - y) = (6y + 2) * 5 - (6y + 2) * y = 30y + 10 - 5y - y^2 = -y^2 + 25y + 10

Now, let's expand the right side of the equation:

(2y - 3)(3y - 1) = (2y - 3) * 3y - (2y - 3) * 1 = 6y^2 - 9y - 2y + 3 = 6y^2 - 11y + 3

Substituting the expanded expressions back into the original equation:

-y^2 + 25y + 10 = 47 - (6y^2 - 11y + 3)

Now, let's simplify the equation by removing the parentheses:

-y^2 + 25y + 10 = 47 - 6y^2 + 11y - 3

Combine like terms:

-y^2 + 25y + 10 = -6y^2 + 11y + 44

Rearrange the equation to bring all terms to one side:

0 = -6y^2 + 11y + 44 + y^2 - 25y - 10

Combine like terms again:

0 = -5y^2 - 14y + 34

To solve this quadratic equation, we can either factor it or use the quadratic formula. However, upon inspection, it does not appear to have any simple integer solutions. Therefore, let's use the quadratic formula:

The quadratic formula states that for an equation in the form of ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In our equation, a = -5, b = -14, and c = 34. Substituting these values into the formula:

y = (-(-14) ± sqrt((-14)^2 - 4(-5)(34))) / (2 * -5) = (14 ± sqrt(196 + 680)) / (-10) = (14 ± sqrt(876)) / (-10)

We have obtained a quadratic equation with complex solutions. By calculating the square root of 876, we find that it is approximately 29.597. Therefore, the solutions for y are:

y ≈ (14 + sqrt(876)) / (-10) y ≈ (14 - sqrt(876)) / (-10)

These solutions cannot be simplified further unless you have specific numerical values for accuracy.