Question

1) X^2= 0,36 2)2x^2-36=0

Answer 1

X²=0.36
x=+-√0.36
x₁=-0.6
x₂=0.6

2x²-36=0
2x²=36
x²=18
x=+-√18
x=+-3√2
x₁=-3√2
x₂=3√2

Answer 2

Let's solve the two equations step by step:

1. $x^2 = 0.36$

To solve for $x$, we can take the square root of both sides of the equation:

$\sqrt{x^2} = \sqrt{0.36}$

$x = \pm \sqrt{0.36}$

Simplifying the square root of 0.36:

$x = \pm 0.6$

Therefore, the solutions to the equation $x^2 = 0.36$ are $x = 0.6$ and $x = -0.6$.

2. $2x^2 - 36 = 0$

Let's solve this quadratic equation by factoring:

First, divide the equation by 2 to simplify it:

$x^2 - 18 = 0$

Now, we can factor the equation:

$x^2 - 18 = (x + \sqrt{18})(x - \sqrt{18})$

Setting each factor equal to zero:

$x + \sqrt{18} = 0$ and $x - \sqrt{18} = 0$

Solving for $x$ in each equation:

$x = -\sqrt{18}$ and $x = \sqrt{18}$

Simplifying the square root of 18:

$x = -3\sqrt{2}$ and $x = 3\sqrt{2}$

Therefore, the solutions to the equation $2x^2 - 36 = 0$ are $x = -3\sqrt{2}$ and $x = 3\sqrt{2}$.