Question

Ln1-log2(1/2)+log(1/7)49=

Answer 1

$ln1-log_{2} \frac{1}{2} +log_{ \frac{1}{7} }49=0-(-1)+(-2)=0+1-2=-1$

Answer 2

To solve the given equation, let's break it down step by step:

Ln(1) - log2(1/2) + log(1/7)49

First, let's simplify the logarithmic expressions:

Ln(1) = 0 (since the natural logarithm of 1 is always 0)

log2(1/2) = log2(1) - log2(2) = 0 - 1 = -1

log(1/7)49 = log(1/7) + log(49) = -log(7) + log(49)

Now, we can substitute the simplified values back into the equation:

0 - 1 + (-log(7) + log(49))

Next, we can use logarithmic properties to simplify further:

-1 + (-log(7) + log(49)) = -1 - log(7) + log(49)

Finally, we can evaluate log(49) and simplify the expression:

-1 - log(7) + log(49) = -1 - log(7) + log(7^2) = -1 - log(7) + 2log(7) = log(7) - 1

Therefore, the solution to the equation Ln(1) - log2(1/2) + log(1/7)49 is simply log(7) - 1.