Question

Log1/6(4-2x)=-2 1/6 основание

Answer 1

тут дробное число в основании или ты это обозначил как логарифм одного от 6?!

 4-2x=1/6^-2

4-2x=6^2 перевернули 

4-2x=36

x=20

элементарно 

Answer 2

log1/6(4-2х)=-2

4-2х=-2

4-2х+2=0

-2х+6=0

-2х=6

х=6/-2

х=-3

 

 

 

 

 

 

 

 

 

 

 

 

Answer 3

To solve the equation log₁/₆(4-2x) = -2, we need to eliminate the logarithm and solve for x.

Step 1: Convert the equation to exponential form. In exponential form, logₐ(b) = c can be rewritten as a^c = b. Therefore, we have: 1/₆^(2) = 4 - 2x

Step 2: Simplify the exponential equation. 1/₆^(2) is equivalent to (6/1)^(2) which is 6² = 36. Thus, we have: 36 = 4 - 2x

Step 3: Solve for x. To isolate x, we'll subtract 4 from both sides: 36 - 4 = -2x

Simplifying further: 32 = -2x

Divide both sides by -2 to solve for x: x = 32 / -2 x = -16

Therefore, the solution to the equation log₁/₆(4-2x) = -2 is x = -16.