Question

Під час спуску із гори швидкість велосипедиста який рухається прямолінійно і рівнопричкорено , змінилася за 5с від 18 км/год до 36 км/год . Яке прискорення велосипедиста ? Який шлях проїхав велосипедист за цей час?

Answer 1

Дано: t=5c; Vo=18 км/ч=18 000 м/3600с=5 м/с; V=36 км/ч=10м/с; а - ? S - ?
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a=(V-Vo)/t=(10-5)/5=1 м/с^2
S=(V^2-Vo^2)/2a=(100-25)/2=37,5 м.
Ответ: 1 м/с^2; 37,5м.
                                      ИЛИ
S=Vot+at^2/2=5*5+1*25/2=25+12,5=37,5 м.

Answer 2

Решение:
a=(V-Vo)/t=(10-5)/5=1 м/с²
S=Vot+at²/2=5•5+1•25/2=25+12,5=37,5 м

Answer 3

Calculation of Acceleration and Distance Traveled

To calculate the acceleration of the cyclist, we can use the formula:

Acceleration (a) = (Final Velocity (v) - Initial Velocity (u)) / Time (t)

Given that the initial velocity (u) is 18 km/h, the final velocity (v) is 36 km/h, and the time (t) is 5 seconds, we can substitute these values into the formula to find the acceleration.

Acceleration (a) = (36 km/h - 18 km/h) / 5 s

Converting the velocities from km/h to m/s:

Acceleration (a) = ((36 km/h - 18 km/h) / 5 s) * (1000 m/1 km) * (1 h/3600 s)

Simplifying the equation:

Acceleration (a) = (18 km/h) * (1000 m/1 km) * (1 h/3600 s) / 5 s

Now, let's calculate the acceleration.

Acceleration (a) = (18 * 1000) / (5 * 3600) m/s^2

Using a calculator, we find that the acceleration of the cyclist is approximately 1 m/s^2.

To calculate the distance traveled by the cyclist during this time, we can use the formula:

Distance (s) = Initial Velocity (u) * Time (t) + 0.5 * Acceleration (a) * Time (t)^2

Substituting the values into the formula:

Distance (s) = 18 km/h * 5 s + 0.5 * 1 m/s^2 * (5 s)^2

Converting the velocity from km/h to m/s:

Distance (s) = (18 km/h) * (1000 m/1 km) * (1 h/3600 s) * 5 s + 0.5 * 1 m/s^2 * (5 s)^2

Simplifying the equation:

Distance (s) = (18 * 1000) / (3600) m + 0.5 * 1 m/s^2 * (5 s)^2

Now, let's calculate the distance traveled.

Distance (s) = (18 * 1000) / (3600) m + 0.5 * 1 m/s^2 * (5 s)^2

Using a calculator, we find that the distance traveled by the cyclist during this time is approximately 25 meters.

Therefore, the acceleration of the cyclist is 1 m/s^2, and the distance traveled by the cyclist is 25 meters.