Question

К источнику постоянного тока с ЭДС 9 В и внутренним сопротивлением 0,5 Ом подключен резистор. Какое количество теплоты выделяется в резисторе за 1 с, если ток в цепи равен 2 А? Сопротивление соединительных проводов пренебрежимо мало.

Answer 1

По закону Ома для полной цепи: I=E/(R+r); R=E/I-r; R=9/2-0.5=4 Ома;
Q=I²Rt; Q=2²*4*1=16 Дж
Ответ: Q=16 Дж

Answer 2

Calculation of Heat Generated in the Resistor

To calculate the amount of heat generated in the resistor, we can use the formula:

Q = I^2 * R * t

Where: - Q is the heat generated in the resistor (in joules) - I is the current flowing through the circuit (in amperes) - R is the resistance of the resistor (in ohms) - t is the time for which the current flows (in seconds)

In this case, the current flowing through the circuit is 2 A, and the resistance of the resistor is 0.5 Ω. We need to find the heat generated in the resistor for a time of 1 second.

Substituting the given values into the formula, we have:

Q = (2 A)^2 * (0.5 Ω) * (1 s)

Calculating this expression, we find:

Q = 2^2 * 0.5 * 1 = 2 J

Therefore, the amount of heat generated in the resistor for 1 second is 2 joules.