Question

З точки А виходить тіло з початковою швидкістю 3 м\с і прискоренням 2м\с^2. через секунду з точки В виходить друге тіло ,що рухається назустріч першому з постійною швидкістю 5м\с. відстань АВ = 100м . скільки часу рухатиметься перше тіло до зустрічі з другим? \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ с точки А значит тело с начальной скоростью 3 м \ с и ускорением 2м \ с ^ 2. через секунду из точки В выходит второе тело, движущееся навстречу первому с постоянной скоростью 5м \ с. расстояние АВ = 100м. сколько времени будет двигаться первое тело к встрече со вторым?

Answer 1

Место встречи изменить нельзя))). Если первый проходит S за время t, то второй 100-S за время t-1 Смотри прикрепление.

Answer 2

Problem Analysis

We are given the following information: - Body A starts from point A with an initial velocity of 3 m/s and an acceleration of 2 m/s^2. - After 1 second, body B starts from point B and moves towards body A with a constant velocity of 5 m/s. - The distance between points A and B is 100 m. - We need to find the time it takes for body A to meet body B.

To solve this problem, we can use the equations of motion to find the time it takes for body A to meet body B.

Solution

Let's break down the problem into two parts: the motion of body A and the motion of body B.

# Motion of Body A

We can use the equation of motion to find the time it takes for body A to meet body B. The equation we will use is:

s = ut + (1/2)at^2,

where: - s is the distance traveled by body A, - u is the initial velocity of body A, - a is the acceleration of body A, and - t is the time taken.

In this case, the distance traveled by body A is the distance between points A and B, which is 100 m. The initial velocity of body A is 3 m/s, and the acceleration is 2 m/s^2.

Substituting these values into the equation, we get:

100 = (3)t + (1/2)(2)t^2.

Simplifying the equation, we have:

2t^2 + 3t - 100 = 0.

We can solve this quadratic equation to find the value of t.

# Motion of Body B

Body B moves towards body A with a constant velocity of 5 m/s. Since the distance between points A and B is 100 m, we can calculate the time it takes for body B to reach point A using the formula:

time = distance / velocity.

Substituting the values, we get:

time = 100 / 5 = 20 seconds.

This means that body B will reach point A after 20 seconds.

# Finding the Time of Meeting

To find the time it takes for body A to meet body B, we need to find the common time at which both bodies reach the same point. Since we have already calculated the time it takes for body B to reach point A (20 seconds), we can substitute this value into the equation we derived for body A:

2t^2 + 3t - 100 = 0.

Solving this equation, we find that the time it takes for body A to meet body B is approximately t ≈ 6.32 seconds.

Answer

Therefore, the first body will take approximately 6.32 seconds to meet the second body.

Please note that the values provided in this response are approximate due to rounding.

Let me know if you need any further assistance!