Question

Температура пара, поступающего в турбину, 227 градусов, а температура холодильника 30 градусов. Определите КПД турбины и колличество теплоты, получаемой от нагревателя каждую секунду, если за это же время бесполезно теряется 12 кДж энергии.

Answer 1

Тн=227+273 =500 К

Тх=30+273=303 К

КПД=(Тн-Тх)/Тн=(500-303)/500=0,394= 39.4 %

 

Qх=12кДж=12000 Дж

 КПД=1-Qх/Qн

0,394=1-12000/Qн

Qн=12000/(1-0,394)=19801,9801980198 =19802 Дж= 19.8 кДж

 

 

Answer 2

Calculation of Turbine Efficiency and Heat Transfer

To determine the efficiency of the turbine and the amount of heat transferred from the heater every second, we need to use the given temperatures and the energy loss.

Given: - Temperature of the steam entering the turbine: 227 degrees Celsius - Temperature of the refrigerator: 30 degrees Celsius - Energy loss: 12 kJ

To calculate the efficiency of the turbine, we can use the formula:

Efficiency = (Useful work output / Heat input)

The useful work output is the difference in heat energy between the steam entering the turbine and the heat energy lost. The heat input is the heat energy of the steam entering the turbine.

Let's calculate the heat input first:

Heat input = Mass flow rate * Specific heat capacity * (Temperature of steam entering the turbine - Temperature of the refrigerator)

Unfortunately, we don't have the mass flow rate or the specific heat capacity of the steam. Without this information, it is not possible to calculate the efficiency of the turbine or the amount of heat transferred from the heater every second.

If you have additional information, such as the mass flow rate or the specific heat capacity of the steam, please provide it so that we can assist you further.