Question

Тело движется равноускоренно в течении 2ч. Начальная скорость тела равна 140 м/с,конечная скорость равна 212 м/с. Определить ускорение и перемещение тела P.S решите пожалуйста очень срочно нужно

Answer 1

Есть хорошая формула для перемещения, выражающаяся через начальную и конечную скорость и ускорения

Само ускорение 
a = (v2-v1)/t = (212-140)/7200 = 0.01 м/с^2

А формула такая

$S = \frac{v_2^2-v_1^2}{2a} = \frac{212^2-140^2}{0.02} = 1267200$

Ответ 1267200 метров

Answer 2

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Answer 3

Given Information:

- The body is moving with constant acceleration for a duration of 2 hours. - The initial velocity of the body is 140 m/s. - The final velocity of the body is 212 m/s.

Calculating Acceleration:

To calculate the acceleration, we can use the formula:

Acceleration (a) = (Final Velocity - Initial Velocity) / Time

Substituting the given values: - Final Velocity (v_f) = 212 m/s - Initial Velocity (v_i) = 140 m/s - Time (t) = 2 hours = 2 * 3600 seconds (since 1 hour = 3600 seconds)

We can calculate the acceleration using the formula:

Acceleration (a) = (212 m/s - 140 m/s) / (2 * 3600 s)

Calculating the acceleration gives us:

Acceleration (a) = 0.0278 m/s^2

Calculating Displacement:

To calculate the displacement, we can use the formula:

Displacement (s) = Initial Velocity * Time + (1/2) * Acceleration * Time^2

Substituting the given values: - Initial Velocity (v_i) = 140 m/s - Time (t) = 2 hours = 2 * 3600 seconds (since 1 hour = 3600 seconds) - Acceleration (a) = 0.0278 m/s^2

We can calculate the displacement using the formula:

Displacement (s) = 140 m/s * (2 * 3600 s) + (1/2) * 0.0278 m/s^2 * (2 * 3600 s)^2

Calculating the displacement gives us:

Displacement (s) = 1008000 m

Answer:

The acceleration of the body is 0.0278 m/s^2 and the displacement of the body is 1008000 m.

Please note that these calculations assume constant acceleration throughout the entire duration of 2 hours.

Let me know if there's anything else I can help you with!