Question

Найти величину задерживающего напряжения при освещении катода излучение с частотой 10^15 Гц если красная граница фотоэффекта 0.5*10^15 ?

Answer 1

Полное решение этой задачи смотри в прикрепленном документе

Answer 2

Calculation of the Stopping Voltage in the Photoelectric Effect

To find the value of the stopping voltage in the photoelectric effect when illuminating the cathode with radiation of frequency 10^15 Hz, we need to use the equation:

eV = hf - φ

Where: - e is the elementary charge (1.6 x 10^-19 C) - V is the stopping voltage (what we want to find) - h is Planck's constant (6.626 x 10^-34 J·s) - f is the frequency of the incident radiation (10^15 Hz) - φ is the work function of the material (in this case, the red threshold frequency, which is 0.5 x 10^15 Hz)

Let's substitute the known values into the equation and solve for V:

eV = hf - φ V = (hf - φ) / e

Substituting the values: - e = 1.6 x 10^-19 C - h = 6.626 x 10^-34 J·s - f = 10^15 Hz - φ = 0.5 x 10^15 Hz

V = ((6.626 x 10^-34 J·s) * (10^15 Hz) - (0.5 x 10^15 Hz)) / (1.6 x 10^-19 C)

Now let's calculate the value of V using the given values:

V = ((6.626 x 10^-34 J·s) * (10^15 Hz) - (0.5 x 10^15 Hz)) / (1.6 x 10^-19 C)

Calculating this expression gives us the value of V.