Вопрос задан 10.05.2019 в 16:21. Предмет Физика. Спрашивает Кушнырева Ульяна.

Дано: ро= 1000кг/м3 g= 10н/кг v= 400см Fa (сила Архимеда) - ?

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Отвечает Пархоменко Кирилл.
Fa=po×g×v
fa= 1000×0.4×10=4000H
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Force of Archimedes (Fa)

The force of Archimedes (Fa) can be calculated using the formula:

Fa = ρ * g * V

Where: - Fa is the force of Archimedes - ρ is the density of the fluid - g is the acceleration due to gravity - V is the volume of the object

In the given problem, the density (ρ) is given as 1000 kg/m^3 and the acceleration due to gravity (g) is given as 10 N/kg. However, the volume (V) is not provided. Therefore, we need to find the volume of the object in order to calculate the force of Archimedes.

Calculation of Volume (V)

The volume (V) can be calculated using the formula:

V = v * A

Where: - V is the volume - v is the velocity of the fluid - A is the cross-sectional area of the object

In the given problem, the velocity (v) is given as 400 cm/s. However, the cross-sectional area (A) is not provided. Therefore, we need to find the cross-sectional area of the object in order to calculate the volume.

Calculation of Cross-Sectional Area (A)

The cross-sectional area (A) can be calculated using the formula:

A = m / ρ

Where: - A is the cross-sectional area - m is the mass of the object - ρ is the density of the fluid

In the given problem, the mass (m) is not provided. Therefore, we need to find the mass of the object in order to calculate the cross-sectional area.

Calculation of Mass (m)

The mass (m) can be calculated using the formula:

m = Q / r

Where: - m is the mass - Q is the flow rate of the fluid - r is the density of the fluid

In the given problem, the flow rate (Q) and the density (r) are not provided. Therefore, we cannot calculate the mass of the object and subsequently the cross-sectional area, volume, and force of Archimedes.

Unfortunately, without the necessary information, we cannot determine the force of Archimedes (Fa) in this specific problem. If you have any additional information or if there is anything else I can assist you with, please let me know!

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