Question

Тепловая машина с КПД 50% за цикл работы отдает холодильнику 100 Дж. Какое количество теплоты за цикл получает машина от нагревателя?

Answer 1

$Q2=100Dg$
$Q1-?$
КПД$= \frac{Q1-Q2}{Q1}$
КПД=$1- \frac{Q2}{Q1}$
$0.5=1- \frac{100}{Q1}$
$Q1=100/(1-0.5)=100/0.5=2*100=200Dg$ Ответ

Answer 2

Calculation of Heat Received by the Engine

To determine the amount of heat received by the engine from the heater, we can use the formula for efficiency:

Efficiency (η) = (Useful Output Energy / Input Energy) x 100%

Given that the efficiency of the engine is 50% and it delivers 100 J of energy to the refrigerator, we can calculate the input energy as follows:

η = (100 J / Input Energy) x 100%

Solving for the input energy:

Input Energy = 100 J / (50% / 100%) = 200 J

Therefore, the engine receives 200 J of heat from the heater during the cycle.

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