Question

Телу массой 200 г сообщили скорость 10 м/с вдоль наклонной поверхности. В результате тело поднялось на высоту 46 м. Какую работу при этом совершила сила трения над бруском?

Answer 1

46*10=460
460-200=260(м)

Answer 2

Calculation of Work Done by Friction

To calculate the work done by the force of friction on the body, we need to determine the distance over which the force acts and the magnitude of the force itself.

Given: - Mass of the body (m) = 200 g = 0.2 kg - Initial velocity of the body (V0) = 10 m/s - Height the body is lifted (h) = 46 m

To find the work done by the force of friction, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.

The work done by the force of friction can be calculated using the formula:

Work = Change in Kinetic Energy

The change in kinetic energy can be calculated as:

Change in Kinetic Energy = Final Kinetic Energy - Initial Kinetic Energy

Since the body comes to rest at the top of the incline, the final kinetic energy is zero.

Therefore, the work done by the force of friction is equal to the initial kinetic energy of the body.

Calculation of Initial Kinetic Energy

The initial kinetic energy of the body can be calculated using the formula:

Initial Kinetic Energy = (1/2) * mass * velocity^2

Substituting the given values:

Initial Kinetic Energy = (1/2) * 0.2 kg * (10 m/s)^2

Simplifying the equation:

Initial Kinetic Energy = 10 J

Therefore, the work done by the force of friction is equal to 10 Joules.

Answer

The force of friction has done 10 Joules of work on the body while it was lifted to a height of 46 meters.