Question

На сколько градусов можно гагреть серебро массой 40г добавив ему 680дж енергии?

Answer 1

Количество теплоты для нагрева тела массой m, с теплоёмкостью  c, при начальной температуре  t1 и конечной  t2 равно Q=c*m*(t2-t1). с=250 Дж/(кг*град) - справочное значение. Тогда t2-t1=Q/(c*m)=680/(250*0,04)=68 градусов.

Ответ: на 68 градусов.

Answer 2

Calculating the Temperature Increase of Silver

To calculate the temperature increase of silver when adding 680 J of energy to it, we can use the formula:

Q = mcΔT

Where: - Q = heat energy added (in joules) - m = mass of the substance (in kilograms) - c = specific heat capacity of the substance (in J/kg°C) - ΔT = change in temperature (in °C)

Specific Heat Capacity of Silver

The specific heat capacity of silver is approximately 0.24 J/g°C [[1]].

Converting Mass to Kilograms

The mass of the silver is 40 grams. To convert this to kilograms, we divide by 1000: - 40 grams = 0.04 kilograms

Calculating the Temperature Change

Now, we can calculate the temperature change using the rearranged formula: ΔT = Q / (mc)

Substitute the values: ΔT = 680 J / (0.04 kg * 0.24 J/g°C) ΔT ≈ 7083.33°C

So, the temperature of the silver would increase by approximately 7083.33°C when adding 680 J of energy to it.