Question

Вагон массой 25 т.,движущийся со скоростью 2м/с сталкивается с неподвижной платформой массой 15 т.Какова скорость их совместного движения

Answer 1

Импульсы
P1+P2=P
P1=v1*m1=2 м/с*25000кг=50000 кг*м/с
Р2=0, так как платформа была неподвижна
Р=(m1+m2)*V
Р1=Р
50000кг*м/с=(25000кг+10000кг)*V
V=50000/35000=1,43 м/с
Не знаю, правильно или нет, но закон сохранения импульса применила

Answer 2

Calculation of the Combined Velocity

To calculate the combined velocity of the wagon and the stationary platform after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Therefore, the momentum of the wagon before the collision is given by the product of its mass (25 tons) and velocity (2 m/s), and the momentum of the stationary platform is given by the product of its mass (15 tons) and velocity (0 m/s).

Using the conservation of momentum principle, we can set up the following equation:

(mass of wagon * velocity of wagon) + (mass of platform * velocity of platform) = (total mass * combined velocity)

Substituting the given values:

(25 tons * 2 m/s) + (15 tons * 0 m/s) = (40 tons * combined velocity)

Simplifying the equation:

50 tons m/s = 40 tons * combined velocity

Dividing both sides of the equation by 40 tons:

combined velocity = (50 tons m/s) / 40 tons

Calculating the combined velocity:

combined velocity = 1.25 m/s

Therefore, the combined velocity of the wagon and the stationary platform after the collision is 1.25 m/s.