Question

Груз массой 2 кг закреплен на пружине жесткостью 200 н/м соверш колебания. мах ускорение груза 10 м/c2 какова мах скорость груза

Answer 1

Вот ответ надеюсь помог
Груз массой 2 кг, закрепленный на пружине жесткостью 200Н/м, совершает гармонические колебания с амплитудой 10см.Какова максимальная скорость груза?



Wп=Wк

kx^2/2=mv^2/2

v=x√(k/m)=0.1*√(200/2)=1 м/с

Ответ 1 м/с

Answer 2

Calculation of Maximum Speed of the Mass on the Spring

To calculate the maximum speed of the mass, we need to use the equation for the maximum acceleration of an object undergoing simple harmonic motion:

a_max = ω^2 * A

Where: - a_max is the maximum acceleration - ω is the angular frequency of the motion - A is the amplitude of the motion

In this case, the mass is attached to a spring with a stiffness of 200 N/m, and it undergoes oscillations. The mass of the object is 2 kg, and the maximum acceleration is given as 10 m/s^2.

To find the angular frequency, we can use the equation:

ω = sqrt(k / m)

Where: - k is the stiffness of the spring - m is the mass of the object

Substituting the given values:

ω = sqrt(200 N/m / 2 kg) = sqrt(100 N/kg) = 10 rad/s

Now we can calculate the maximum speed using the equation:

v_max = ω * A

Substituting the given values:

v_max = 10 rad/s * 10 m = 100 m/s

Therefore, the maximum speed of the mass on the spring is 100 m/s.