Question

Помогите решить задачу по физике. ЗН Ома.

Answer 1

1/R(1-3) = (1/2)+(1/6)+(1/12) = 9/12 = 3/4. R(1-3) = 4/3 Ом.
R(5-7) = 10/2 = 5 Ом.
R(1-8) = (4/3)+5+5+10 = 21(1/3) =(64/3) Ом.
I(1-8) = 120/(64/3) = 360/64 = (45/8) = 5,625 A.
U(1-3) = (45/8)*(4/3) = ( 45/6) = 7,5 B.
I1 = 7,5/2 = 3,75 A.
I2 = 7,5/6 = 15/12 = 5/4 = 1,25 A.
I3 = 7,5/12 = 15/24 = 5/8 = 0,625 A.
U4 = 5*(45/8) =  (225/8) = 28,125 B.
U(5-7) = 5*(45/8) =  (225/8) = 28,125 B.
I5 = I(6-7) = (45/8)/2 = (45/16) = 2,8125 A.
I8 = (45/8) =  5,625 A.
U8 = (45/8)*10 =  (450/8) =  56,25 B.