Question

На какую глубину может погрузиться батискаф в морской воде, если стекло иллюминатора батискафа выдерживает давление 79,31 МПа? Плотность морской воды ρ=1030кг/м в 3-й степени g≈10м/с во 2-й степени

Answer 1

Дано:

p=79,31мПа

ρ=1030 кг/м³

g≈10 м/с²

Найти:

h=?

Формула:

p=ρgh

h=p:(ρ*g)

Решение:

h=p:(ρ*g)=79310000:(1030 кг/м³*10 м/с)²=770000м=770 км

Ответ:Батискаф может погрузиться в воду на глубину 770 км

Answer 2

Depth Capability of Bathyscaphe with Given Glass Pressure Resistance

The depth to which a bathyscaphe can descend in seawater can be calculated based on the pressure resistance of the glass illuminator and the density of seawater.

The pressure at a certain depth in a fluid can be calculated using the formula: \[ P = \rho \cdot g \cdot h \] Where: - \( P \) = pressure - \( \rho \) = density of the fluid - \( g \) = acceleration due to gravity - \( h \) = depth

Given: - Pressure resistance of the glass illuminator: 79.31 MPa - Density of seawater \( \rho = 1030 \, \text{kg/m}^3 \) - Acceleration due to gravity \( g \approx 10 \, \text{m/s}^2 \)

We can rearrange the formula to solve for depth: \[ h = \frac{P}{\rho \cdot g} \]

Substituting the given values: \[ h = \frac{79.31 \times 10^6 \, \text{Pa}}{1030 \, \text{kg/m}^3 \times 10 \, \text{m/s}^2} \]

Calculating the depth: \[ h \approx 7700 \, \text{m} \]

The bathyscaphe can descend to a depth of approximately 7700 meters in seawater, given that the glass illuminator can withstand a pressure of 79.31 MPa.