Question

Катящийся со скоростью 1м/ с бильярдный шар встречает на своем пути точно такой же покоящийся шар и останавливается. Найти скорость другого шара после столкновения.

Answer 1

ПО ЗАКОНУ СОХРАНЕНИЯ ИМПУЛЬСА:
m*V₁+ 0=0 +m*V₂
V₂=V₁=1м/с

Answer 2

Problem Analysis

We are given that a rolling billiard ball with a speed of 1 m/s collides with another stationary billiard ball. We need to find the speed of the second ball after the collision.

Solution

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is defined as the product of its mass and velocity. Since both balls have the same mass, we can simplify the equation.

Let's assume the mass of each ball is m and the initial velocity of the rolling ball is v. After the collision, the rolling ball comes to a stop, so its final velocity is 0. The second ball, which was initially stationary, will acquire a velocity v'.

Using the principle of conservation of momentum, we can write the equation:

m * v = m * v' + m * 0

Simplifying the equation, we get:

v = v'

Therefore, the speed of the second ball after the collision is equal to the speed of the rolling ball before the collision, which is 1 m/s.

Conclusion

The speed of the second ball after the collision is 1 m/s.