Question

Дифракционная решетка освещается светом с частотой 7,5∙1014 с-1. Период решетки 2 мкм. Определить общее число главных максимумов, которые позволяет наблюдать данная дифракционная решетка. ...

Answer 1

Ответ в прикреплении

Answer 2

Calculation of the Total Number of Principal Maxima

To determine the total number of principal maxima observed by the given diffraction grating, we can use the formula:

n = (2d/λ) + 1

where: - n is the total number of principal maxima - d is the period of the grating - λ is the wavelength of the incident light

Given: - The period of the grating (d) is 2 μm (2 × 10^-6 m) - The frequency of the incident light is 7.5 × 10^14 s^-1

To find the wavelength (λ), we can use the formula:

c = λν

where: - c is the speed of light (approximately 3 × 10^8 m/s) - λ is the wavelength - ν is the frequency

Substituting the values, we can solve for λ:

λ = c/ν = (3 × 10^8 m/s) / (7.5 × 10^14 s^-1)

Let's calculate λ first:

λ = (3 × 10^8 m/s) / (7.5 × 10^14 s^-1)

Using a calculator, we find:

λ ≈ 4 × 10^-7 m

Now, we can substitute the values of d and λ into the formula for n:

n = (2d/λ) + 1 = (2 × 10^-6 m) / (4 × 10^-7 m) + 1

Simplifying the expression:

n = 5 + 1 = 6

Therefore, the given diffraction grating allows the observation of 6 principal maxima.