Question

троллейбус движущийся со скоростью 36 км/ч останавливается при торможении в течении 4 с. С каким постоянным ускорением движется он при торможении?

Answer 1

по формуле: v=v0+at, получаем что v=0. а t=4 и что v0=36. подставим 0=36+4a

4a=-36

a=-9

 

Answer 2

Calculation of Constant Acceleration during Braking

To determine the constant acceleration of the trolleybus during braking, we can use the formula:

acceleration = change in velocity / time

Given that the trolleybus is moving at a speed of 36 km/h and comes to a stop in 4 seconds, we can calculate the acceleration.

First, let's convert the speed from kilometers per hour to meters per second:

36 km/h = (36 * 1000) m / (60 * 60) s = 10 m/s.

Now, we can calculate the acceleration using the formula mentioned earlier:

acceleration = (final velocity - initial velocity) / time

Since the trolleybus comes to a stop, the final velocity is 0 m/s, the initial velocity is 10 m/s, and the time is 4 seconds.

acceleration = (0 - 10) m/s / 4 s = -10 m/s².

Therefore, the trolleybus moves with a constant acceleration of -10 m/s² during braking. The negative sign indicates that the trolleybus is decelerating or slowing down.

Please let me know if there's anything else I can help you with!