Question

Найти КПД тепловой машины, если за один цикл она совершила работу 3 кДж, а холодильнику было передано 13,4 кДж теплоты.

Answer 1

Η=A\Q1*100%=3\15,4=19,5%
Q1=A+Q2=15,4kДж

Answer 2

Calculation of Thermal Efficiency (КПД) of a Heat Engine

To find the thermal efficiency (КПД) of a heat engine, we need to know the work done by the engine and the amount of heat transferred to the refrigerator.

Given: - Work done by the engine in one cycle = 3 kJ - Heat transferred to the refrigerator = 13.4 kJ

The thermal efficiency (КПД) of a heat engine is defined as the ratio of the work done by the engine to the heat transferred to the engine:

КПД = (Work done by the engine) / (Heat transferred to the engine)

Substituting the given values:

КПД = 3 kJ / 13.4 kJ

To calculate the thermal efficiency, we need to convert the units to the same base unit. Let's convert both values to joules:

КПД = 3000 J / 13400 J

Simplifying the expression:

КПД = 0.2239

Therefore, the thermal efficiency (КПД) of the heat engine is approximately 0.2239, or 22.39%.

Please note that the provided search results did not directly provide the formula for calculating thermal efficiency. However, the calculation is a standard formula used in thermodynamics.

provides a table with different efficiency values for a heat engine, but it does not directly relate to the given question. and do not provide relevant information for the given question.