Question

Мальчик весом 200Н держит на поднятой вверх руке гирю весом 50Н.С какой силой он давит на землю?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

Answer 1

|P|=mg=|N|
P(об.)= P1+P2+P3+...
P=200H+50H=250H

Answer 2

Calculating the Force Exerted on the Ground

To calculate the force exerted on the ground by the boy holding a weight of 50N in his raised hand, we need to consider the principle of equilibrium. According to Newton's third law of motion, every action has an equal and opposite reaction. In this case, the force exerted by the boy on the weight is equal in magnitude but opposite in direction to the force exerted by the weight on the boy's hand.

Since the boy is holding the weight in his raised hand, the force exerted by the weight on the boy's hand is equal to its weight, which is 50N. Therefore, the force exerted by the boy on the ground is also 50N, in the opposite direction.

So, the boy is exerting a force of 50N on the ground.