Question

Высота наклонной плоскости 1м, а длина 15м. Для подъема по ней груза весом 50 H потребовалась сила 10 H. определите кпд этой наклонной плоскости(помогите, от этого зависит оценка за год)

Answer 1

η = A(полезн)/A(затрачен)
A(полезн) = Fтяж*h где (Fтяж = P) и h = 1 м 
A(затрачен) = F*S где F=10 Н, а S=15 м

η = P*h/F*S = 50*1/10*15 ≈ 0,33 или же ≈ 33% 

Answer 2

Calculation of Efficiency of Inclined Plane

To calculate the efficiency of an inclined plane, we need to know the input work and the output work. In this case, the input work is the work done by the force applied to lift the load, and the output work is the work done against gravity to lift the load.

Given: - Height of the inclined plane (h) = 1 m - Length of the inclined plane (l) = 15 m - Force applied (F) = 10 H - Weight of the load (W) = 50 H

To calculate the input work, we use the formula:

Input Work (Wi) = Force (F) x Distance (d)

Since the force is applied parallel to the inclined plane, the distance is equal to the length of the inclined plane. Therefore:

Wi = F x l

Substituting the given values:

Wi = 10 H x 15 m

To calculate the output work, we use the formula:

Output Work (Wo) = Weight (W) x Height (h)

Substituting the given values:

Wo = 50 H x 1 m

Now, we can calculate the efficiency (η) of the inclined plane using the formula:

Efficiency (η) = (Output Work / Input Work) x 100

Substituting the calculated values:

η = (Wo / Wi) x 100

Let's calculate the efficiency:

η = (50 H x 1 m) / (10 H x 15 m) x 100

Simplifying the expression:

η = (50 / 10) x (1 / 15) x 100

η = 5 x (1 / 15) x 100

η = 33.33%

Therefore, the efficiency of this inclined plane is approximately 33.33%.

Please note that the calculation assumes ideal conditions and does not take into account factors such as friction or other losses.