Question

Сколько энергии E нужно затратить, чтобы расплавить 14 кг льда при температуре 0ºС? Удельная теплота плавления льда равна 330 кДж/кг.

Answer 1

T=0 C
λ=330*10³ Дж/кг
m=14кг
Е-?

Е=λm
E=330*1000*14=4620000 Дж = 4,62 МДж

Answer 2

Calculating the Energy Required to Melt Ice

To calculate the energy required to melt 14 kg of ice at 0ºC, we can use the formula:

Q = m * L

Where: - Q is the energy required (in joules) - m is the mass of the substance (in kg) - L is the specific latent heat of fusion (in J/kg)

Given: - m = 14 kg - L = 330 kJ/kg or 330,000 J/kg (1 kJ = 1000 J)

We can now calculate the energy required to melt the ice.

Calculation

Using the formula Q = m * L: - Q = 14 kg * 330,000 J/kg - Q = 4,620,000 J

So, the energy required to melt 14 kg of ice at 0ºC is 4,620,000 joules.