Question

Пружинный маятник совершил 90 колебаний за 1,5 минуты. Найдите период, частоту колебаний.

Answer 1

1)T=t/N, где

   Т- период

   t- время

   N- количество колебаний

   Т=5/20=0,25c.

2) ν(это буква "ню")=N/t, где

   ν-частота

   t-время

   N-количество колебаний

   ν=90/5=4Гц

Ответ: 0,90c; 4Гц

Answer 2

Calculation of Period and Frequency

To find the period and frequency of a spring pendulum, we can use the formula:

Period (T) = Time / Number of Oscillations

In this case, the spring pendulum completed 90 oscillations in 1.5 minutes.

Let's calculate the period and frequency:

Period (T) = 1.5 minutes / 90 oscillations

To convert the period to seconds, we need to multiply it by 60:

Period (T) = (1.5 minutes / 90 oscillations) * 60 seconds/minute

Now, let's calculate the period:

Period (T) = (1.5 * 60) / 90 seconds

Simplifying the equation:

Period (T) = 1 second

The period of the spring pendulum is 1 second.

To calculate the frequency, we can use the formula:

Frequency (f) = 1 / Period (T)

Substituting the value of the period:

Frequency (f) = 1 / 1 second

Simplifying the equation:

Frequency (f) = 1 Hz

The frequency of the spring pendulum is 1 Hz.

Therefore, the period of the spring pendulum is 1 second, and the frequency is 1 Hz.