Question

тело бросили вертикально вверх с начальной скоростью 6 м/с.На какой высоте оно будет через 0,4 с?

Answer 1

h=v0t-gt^2/2

h=6*0.4-10*0.4^2/2=2.4-0.8=1.6 (м)

Ответ: 1,6 метров

Answer 2

Calculation of the Height

To calculate the height of an object thrown vertically upwards with an initial velocity of 6 m/s after 0.4 seconds, we can use the equations of motion.

The equation for the height of an object in free fall is given by:

h = h0 + v0 * t - (1/2) * g * t^2 Where: - h is the final height - h0 is the initial height (which is 0 in this case since the object is thrown vertically upwards) - v0 is the initial velocity (6 m/s in this case) - t is the time (0.4 seconds in this case) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values into the equation, we can calculate the height:

h = 0 + 6 * 0.4 - (1/2) * 9.8 * (0.4)^2

Simplifying the equation:

h = 0 + 2.4 - (1/2) * 9.8 * 0.16

h = 2.4 - 0.0784

h ≈ 2.3216 meters

Therefore, the object will reach a height of approximately 2.3216 meters after 0.4 seconds.