Question

2) Напишіть рівняння альфа розпаду ядра 239-94Pu та визначіть кількість нейтронів в утвореному 94 ядрі

Answer 1

$\frac{239}{94} Pu= \frac{4}{2} \alpha + \frac{235}{92} U$

у исходного ядра 
$\frac{239}{94} Pu$ протонов 94 нейтронов 145
у получившегося ядра
$\frac{235}{92} U$  протонов 92 нейтронов 142

Answer 2

Alpha Decay Equation and Neutron Count

The alpha decay equation for the nucleus 239-94Pu can be represented as follows:

239-94Pu → 4-2He + 235-92U

This equation indicates that the nucleus of 239-94Pu undergoes alpha decay, emitting an alpha particle (4-2He) and transforming into a new nucleus, 235-92U [[1]].

To determine the number of neutrons in the resulting 94th element, which is 235-92U, we can use the following formula:

Number of neutrons = Atomic mass - Atomic number

For the nucleus 235-92U: - Atomic mass = 235 - Atomic number = 92

Number of neutrons = 235 - 92 = 143

Therefore, the number of neutrons in the resulting 94th element (235-92U) is 143.