Question

Определите период колебаний тела массой m=2кг, скрепленного с пружиной жесткостью K=2000 Н/м

Answer 1

T=2*pi*sqrt(m/k)=6,28*sqrt(2/200)=0,628 c

Answer 2

Calculating the Period of Oscillation for a Mass-Spring System

To determine the period of oscillation for a body of mass \( m = 2 \, \text{kg} \) attached to a spring with a stiffness of \( K = 2000 \, \text{N/m} \), we can use the formula for the period of oscillation of a mass-spring system:

Period of Oscillation (T) = \( 2\pi \sqrt{\frac{m}{K}} \)

Calculation

Substitute the given values into the formula: \( T = 2\pi \sqrt{\frac{2}{2000}} \)

Solving for T: \( T = 2\pi \sqrt{0.001} \) \( T \approx 2\pi \times 0.0316 \) \( T \approx 0.1989 \, \text{s} \)

Therefore, the period of oscillation for the given mass-spring system is approximately 0.1989 seconds.