Question

В сосуде находится газ при температуре 273 С. Определите среднюю кинетическую энергию хаотического движения молекул газа

Answer 1

Ек=(3/2)k*T
где k- постоянная Больцмана, равная 1.38х10^-23
Т преобразуем в Кельвины= 273+273=546 К
Ек=(3/2)*1.38*10^-23*546=1.1*10^-20 Дж
Ответ: 1.1*10^-23 Дж

Answer 2

Calculation of Average Kinetic Energy

To determine the average kinetic energy of the gas molecules, we can use the formula:

E_avg = (3/2) * k * T

Where: - E_avg is the average kinetic energy of the gas molecules. - k is the Boltzmann constant, approximately equal to 1.38 × 10^-23 J/K. - T is the temperature of the gas in Kelvin.

Given that the temperature of the gas is 273°C, we need to convert it to Kelvin by adding 273 to the Celsius temperature:

T = 273 + 273 = 546 K

Now we can substitute the values into the formula to calculate the average kinetic energy:

E_avg = (3/2) * (1.38 × 10^-23 J/K) * 546 K

Calculating this expression gives us the average kinetic energy of the gas molecules.

Please note that the actual value of the average kinetic energy will depend on the specific gas and its properties. The formula provided above is a general expression applicable to ideal gases.