Question

1 автомобіль массою 4.6 т рушає з місця на підйомі що дорівнює 0.025 і рухаючись рівноприскорено за 40 сек проходить 200 м .Визначте витрату бензину на цій ділянці якщо коефіцієнт опору 0.02 а ккд 20%2 хлопчик наповнив три четвертих склянки місткістю 200 см (кубічних) кипятком а решту доповнив холодною водою .Визначте яка температура води встановилася якщо холодна вода мала температуру 20 градусів цельсія

Answer 1

1)
S=at^2/2 - путь при равноускоренном движении
a=2S/t^2 - ускорение при равноускоренном движении
ma=F-mg*sin(alpha)-мю*mg*cos(alpha) - 2 закон ньютона
F=ma+mg*sin(alpha)+мю*mg*cos(alpha)=m*(2S/t^2+g*(sin(alpha)+мю*cos(alpha) ) ) - сила тяги
A = F*S = S*m*(2S/t^2+g*(sin(alpha)+мю*cos(alpha) ) ) - работа силы тяги
Q=M*q - энергия сгорания бензина
A=Q*КПД/100% - уравнение теплового баланса
S*m*(2S/t^2+g*(sin(alpha)+мю*cos(alpha) ) ) = M*q * КПД/100% - подставляем
M = S*m*(2S/t^2+g*(sin(alpha)+мю*cos(alpha) ) )*100%/(q * КПД) - масса бензина
M = 200*4600*(2*200/40^2+9,8*(sin(0,025)+0,02*cos(0,025) ) )*100/(44000000 * 20) кг = 0,072231838 кг ~ 72,2 гр
V = M/ro = 72,2/0,75 мл = 96,26666667 ~ 96,3 мл = 96,3*10 ^(-6) м^3
2)
m1c(T-T1)+m2c(T-T2)=0
T=(m1*T1+m2*T2)/(m1+m2)=m1/(m1+m2)*T1+m2/(m1+m2)*T2=3/4*100+1/4*20 C = 80 C

Answer 2

Calculation of Fuel Consumption

To calculate the fuel consumption for the given scenario, we need to consider the mass of the car, the distance traveled, the coefficient of resistance, and the efficiency of the car. Let's break down the problem step by step.

Given information: - Mass of the car: 4.6 tons (or 4,600 kg) - Distance traveled: 200 meters - Coefficient of resistance: 0.02 - Efficiency (or fuel efficiency): 20%

First, let's calculate the work done by the car to move up the slope. The work done is equal to the change in potential energy:

Work = mgh

Where: - m is the mass of the car - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height of the slope, which is given as 0.025

Work = 4600 kg * 9.8 m/s^2 * 0.025 m

Now, let's calculate the energy required to cover the horizontal distance of 200 meters. The energy required is equal to the work done against the resistance force:

Energy = Work + Resistance Energy

The resistance energy can be calculated using the formula:

Resistance Energy = Resistance Force * Distance

The resistance force can be calculated using the formula:

Resistance Force = Coefficient of Resistance * Weight

Where: - Weight = mass * g

Resistance Force = 0.02 * (4600 kg * 9.8 m/s^2)

Now, we can calculate the resistance energy:

Resistance Energy = 0.02 * (4600 kg * 9.8 m/s^2) * 200 m

Finally, we can calculate the total energy required:

Energy = Work + Resistance Energy

Now, let's calculate the fuel consumption. The fuel consumption is the energy required divided by the efficiency:

Fuel Consumption = Energy / Efficiency

Please note that the fuel consumption will be in the same units as the energy used (e.g., Joules or kilowatt-hours). If you would like the fuel consumption in liters or gallons, we would need additional information such as the energy content of the fuel.

Let's calculate the fuel consumption using the given values.