Question

Камень брошен с вышки в гори­ зонтальном направлении со скоростью U>0 = 20 м/с. Определите скорость v камня в конце второй секунды полета.

Answer 1

Vy=gt²/2=10*4/2=20 м/с
По теореме Пифагора:
V²=20²+20²=2*20²
V=20√2≈28 м/с

Answer 2

Calculation of the stone's velocity at the end of the second second of flight

To determine the velocity of the stone at the end of the second second of flight, we need to consider the initial velocity of the stone and the acceleration due to gravity.

Given: - Initial velocity (u) = 20 m/s (thrown horizontally) - Time (t) = 2 seconds

We know that the acceleration due to gravity (g) is approximately 9.8 m/s^2.

The formula to calculate the final velocity (v) of an object in free fall is:

v = u + gt

where: - v is the final velocity - u is the initial velocity - g is the acceleration due to gravity - t is the time

Substituting the given values into the formula, we have:

v = 20 + (9.8 * 2)

Calculating this expression, we find:

v = 20 + 19.6 = 39.6 m/s

Therefore, the velocity of the stone at the end of the second second of flight is 39.6 m/s