
Два тела массами 200 и 500 ,движущиеся навстречу друг другу,после столкновения остановились.Чему
равна начальная скорость 2 тела,если первое двигалось со скоростью 2 м\с?

Ответы на вопрос

Значит так
Масса первого тела 200г = 0.2 кг
Масса второго тела 500г = 0.5 кг
Скорость первого тела - 2 м/с
Начальная скоорость второго тела (V2) = ?
Задачу можно решить соотношением
0.2/0.5 = х/2
2/5 = х/2
Отсюда х=4/5= 0.8 м/с
Ответ: скорость второго тела равна 0.8 м/с



m1v1-m2v2=0, где v1 и v2 - скорости двух тел.
0.2*2-0.5*V2=0
v2=0.8
Ответ: 0.8 м/c



Calculation of Initial Velocity
To calculate the initial velocity of the two bodies, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is given by the product of its mass and velocity. Therefore, we can write the equation:
Initial momentum of the first body + Initial momentum of the second body = Final momentum of the first body + Final momentum of the second body
Let's denote the mass of the first body as m1 (200 kg) and the mass of the second body as m2 (500 kg). The initial velocity of the first body is given as 2 m/s.
Using this information, we can calculate the initial velocity of the second body.
Calculation:
The initial momentum of the first body (m1) is given by: Initial momentum of the first body = m1 * initial velocity of the first body
The final momentum of the first body (m1) is given by: Final momentum of the first body = m1 * final velocity of the first body
The initial momentum of the second body (m2) is given by: Initial momentum of the second body = m2 * initial velocity of the second body
The final momentum of the second body (m2) is given by: Final momentum of the second body = m2 * final velocity of the second body
Since the bodies come to a stop after the collision, the final velocity of both bodies is 0 m/s.
Now, let's substitute the given values into the equations and solve for the initial velocity of the second body.
Initial momentum of the first body + Initial momentum of the second body = Final momentum of the first body + Final momentum of the second body
(m1 * initial velocity of the first body) + (m2 * initial velocity of the second body) = (m1 * final velocity of the first body) + (m2 * final velocity of the second body)
(200 kg * 2 m/s) + (500 kg * initial velocity of the second body) = (200 kg * 0 m/s) + (500 kg * 0 m/s)
400 kg m/s + 500 kg * initial velocity of the second body = 0 kg m/s
500 kg * initial velocity of the second body = -400 kg m/s
initial velocity of the second body = -400 kg m/s / 500 kg
initial velocity of the second body = -0.8 m/s
Therefore, the initial velocity of the second body is -0.8 m/s.
Please note that the negative sign indicates that the second body was moving in the opposite direction to the first body before the collision.


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