Question

15 баллов. Каков заряд конденсатора пускового устройства электродвигателя, если энергии, запасённой в конденсаторе, достаточно, чтобы поднять груз массой 160 кг на высоту 10 м? Ёмкость конденсатора равна 200 мкФ. Считайте, что .

Answer 1

Eп=m*g*h
Eп=160*10*10=16000 Дж
Eп=Wр
Wр=q^2/(2*C)
q^2=Wp*2*C
q^2=16 000*2*200*10^-6
q^2=6 400 000*10^-6=6.4 кл
q^2=6.4 Кл^2
q=корень квадратный из(6.4 Кл^2)=2.5 кл

Answer 2

Calculation of the Capacitor Charge for the Motor Starting Device

To calculate the charge of the capacitor in the motor starting device, we need to determine the potential energy required to lift a mass of 160 kg to a height of 10 m.

The potential energy (PE) can be calculated using the formula:

PE = mgh

Where: - m is the mass (160 kg) - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height (10 m)

Substituting the values into the formula, we get:

PE = 160 kg * 9.8 m/s^2 * 10 m = 15,680 J

The potential energy required to lift the mass to a height of 10 m is 15,680 J.

Now, we can calculate the charge (Q) stored in the capacitor using the formula:

Q = CV

Where: - Q is the charge stored in the capacitor - C is the capacitance of the capacitor (200 μF) - V is the voltage across the capacitor

To find the voltage across the capacitor, we can use the formula:

V = √(2PE/C)

Substituting the values into the formula, we get:

V = √(2 * 15,680 J / 200 μF) = √(78.4 V) = 8.84 V

The voltage across the capacitor is approximately 8.84 V.

Finally, we can calculate the charge stored in the capacitor:

Q = CV = (200 μF) * (8.84 V) = 1.768 mC

Therefore, the charge of the capacitor in the motor starting device is approximately 1.768 milliCoulombs (mC).

Please note that the calculations provided are based on the given information and assumptions.