Question

Проволочная спираль сопротивление которой в нагретом состоянии равно 55 ом включина в сеть с наприжением 127 в.какое количество теплоты выделяет спираль за 1 минуту?

Answer 1

Q = I^2(это квадрат) * R * t
Q = I^2 * R * t
Q = 127^2 В * 55 Ом * 60 с
Q = 16129 В * 55 Ом * 60 с
Q = 53225700 Дж = 53225.7 kДж = 53.226 MДж
Ответ: запиши как хочешь. Смысл один и тот же.

Answer 2

Calculation of Heat Generated by the Wire

To calculate the amount of heat generated by the wire in 1 minute, we need to use the formula:

Q = I^2 * R * t

Where: - Q is the heat generated (in joules) - I is the current flowing through the wire (in amperes) - R is the resistance of the wire (in ohms) - t is the time (in seconds)

In this case, we are given that the resistance of the wire when heated is 55 ohms and the voltage across the wire is 127 volts. We need to find the current flowing through the wire and convert the time from minutes to seconds.

Calculation Steps

1. Calculate the current flowing through the wire using Ohm's Law: - I = V / R, where V is the voltage and R is the resistance. - I = 127 V / 55 Ω = 2.309 A.

2. Convert the time from minutes to seconds: - 1 minute = 60 seconds.

3. Substitute the values into the formula: - Q = (2.309 A)^2 * 55 Ω * 60 s.

4. Calculate the heat generated: - Q = 2.309^2 * 55 * 60 = 18,595.47 joules.

Therefore, the wire generates approximately 18,595.47 joules of heat in 1 minute.