Question

С неподвижно зависшего с вертолета сбросили без начальной скорости два груза Причем второй на 1 секунду позже первого определите расстояние между грузами через 4 секунды после начала движения первого груза

Answer 1

Дано:
t=4c
g=10m/c^2
найти
S
РЕШЕНИЕ
S=at^2/2; где а=g
Найдем время полета второго груза
t1=t-1=4-1=3c
S=10×16/2=80m
S1=10×9/2=45m
Найдем разность между этими растояниями
Sр= S-S1=35m это растояние между двумя грузами

Answer 2

Calculating the Distance Between Two Dropped Objects

To calculate the distance between two objects dropped from a stationary helicopter, we can use the equations of motion to determine the positions of the objects at different times.

Initial Conditions

- The first object is dropped from the stationary helicopter. - The second object is dropped 1 second later.

Using Equations of Motion

We can use the equations of motion to calculate the positions of the objects at different times. The equation for the position of an object under constant acceleration is given by: $$ s = ut + \frac{1}{2}at^2 $$ Where: - \( s \) = displacement - \( u \) = initial velocity - \( a \) = acceleration - \( t \) = time

Calculating the Distance

Let's calculate the distance between the two objects after 4 seconds from the start of the motion of the first object.

- For the first object: - \( u_1 = 0 \) (initial velocity as it is dropped without any initial speed) - \( a_1 = 9.81 \, m/s^2 \) (acceleration due to gravity)

Using the equation of motion, the displacement of the first object after 4 seconds can be calculated: $$ s_1 = 0 \times 4 + \frac{1}{2} \times 9.81 \times 4^2 $$

- For the second object: - \( u_2 = 0 \) (initial velocity as it is dropped without any initial speed) - \( a_2 = 9.81 \, m/s^2 \) (acceleration due to gravity)

Using the equation of motion, the displacement of the second object after 3 seconds can be calculated: $$ s_2 = 0 \times 3 + \frac{1}{2} \times 9.81 \times 3^2 $$

Results

After calculating the displacements for both objects, we can determine the distance between them after 4 seconds.

The distance between the two objects after 4 seconds is the absolute difference between their displacements.

Let's calculate the exact values.