Question

Змішали 10 кг води при температурі 20°С і 10 кг води при температурі 80°С. Яка температура суміші? Помогите срочно пожалуйста! Умоляю срочно!

Answer 1

Calculating the Final Temperature of the Mixture

To calculate the final temperature of the mixture, we can use the principle of conservation of energy, which states that the total internal energy of an isolated system remains constant. This principle can be expressed through the equation:

m1c1(T1) + m2c2(T2) = (m1 + m2)cf(Tf)

Where: - m1 and m2 are the masses of the two substances - c1 and c2 are the specific heat capacities of the two substances - T1 and T2 are the initial temperatures of the two substances - cf is the specific heat capacity of the final mixture - Tf is the final temperature of the mixture

Applying the Formula to the Given Scenario

In this case, we have: - m1 = 10 kg (mass of the first water sample) - T1 = 20°C (initial temperature of the first water sample) - m2 = 10 kg (mass of the second water sample) - T2 = 80°C (initial temperature of the second water sample)

The specific heat capacity of water is approximately 4.18 J/g°C.

Calculating the Final Temperature

Using the given values and the formula, we can calculate the final temperature of the mixture:

m1c1(T1) + m2c2(T2) = (m1 + m2)cf(Tf)

Substituting the values: (10 kg)(4.18 J/g°C)(20°C) + (10 kg)(4.18 J/g°C)(80°C) = (10 kg + 10 kg)cf(Tf)

Solving for Tf: (10 kg)(4.18 J/g°C)(20°C) + (10 kg)(4.18 J/g°C)(80°C) = (20 kg)cf(Tf)

Calculation Result

The final temperature of the mixture can be calculated using the above equation.