Question

Кирпич падает без начальной скорости с высоты Н=9м. Определите скорость кирпича на высоте h=4м. Ускорение свободного падения примите равным g=10м/с (копирование с других сайтов не принимается)

Answer 1

Кирпич падает без начальной скорости с высоты Н=9м. Определите скорость кирпича на высоте h=4м. Ускорение свободного падения примите равным g=10м/с

Answer 2

Calculation of the Brick's Velocity at Height h = 4m

To determine the velocity of the brick at a height of h = 4m, we can use the principles of free fall and the equations of motion.

The initial height of the brick is H = 9m, and the acceleration due to gravity is g = 10m/s². We can assume that the brick is dropped from rest, meaning it has an initial velocity of 0m/s.

Using the equation of motion for free fall:

h = (1/2)gt²

where h is the height, g is the acceleration due to gravity, and t is the time.

We can rearrange this equation to solve for time:

t = sqrt(2h/g)

Substituting the given values:

t = sqrt(2 * 4 / 10) = sqrt(8/10) = sqrt(0.8) ≈ 0.8944s

Now that we have the time it takes for the brick to fall to a height of 4m, we can use another equation of motion to calculate the velocity at that height:

v = gt

Substituting the values:

v = 10 * 0.8944 ≈ 8.944 m/s

Therefore, the velocity of the brick at a height of 4m is approximately 8.944 m/s.

Please note that the above calculations assume no air resistance and that the brick is dropped vertically without any horizontal motion.