Question

Сила, вращающая рычаг по часовой стрелке, равна 10 Н, её плечо 15 см. Плечо силы, вращающей рычаг против часовой стрелки, равно 30 см. Чему равна эта сила, если рычаг находится в равновесии

Answer 1

F1*L1= F2*L2

10*0,15= F2*0,3

F2= 5 H

Answer 2

Calculation of the Force in Equilibrium

To calculate the force in equilibrium, we need to consider the torques acting on the lever. Torque is the product of force and the perpendicular distance from the pivot point to the line of action of the force.

Given information: - Clockwise torque: Force = 10 N, Lever arm = 15 cm = 0.15 m - Counterclockwise torque: Lever arm = 30 cm = 0.3 m

To find the force in equilibrium, we can set up the equation:

Sum of clockwise torques = Sum of counterclockwise torques

Let's calculate the torques:

Clockwise torque = Force * Lever arm = 10 N * 0.15 m = 1.5 Nm

Counterclockwise torque = Force * Lever arm = F * 0.3 m

Since the lever is in equilibrium, the torques are equal:

1.5 Nm = F * 0.3 m

Now we can solve for the force:

F = 1.5 Nm / 0.3 m = 5 N

Therefore, the force required to keep the lever in equilibrium is 5 N.