Question

С наклонной плоскости,имеющей угол наклона 40 градусов,соскальзывает тело массой 10 кг.Определите силу трения,если ускорение тела равно 2 м/с Главное рисунок ) помогите плиз

Answer 1

Для начала нужно нарисовать рисунок, расставив все силы (сопротивления опоры, трения, тяжести, ускорение). Направить ось Y по силе сопротивления опоры, а X по плоскости, на которой находится тело.
По II закону Ньютона:
ma=mg+F(тр)+N (с векторами)
на ось OX: ma=F(тр)+mg*cos40
Подставим: 10*2=F(тр)+10*10*(√2/2)
20=F(тр)+50*√2
F(тр)= -50,7 Н

Answer 2

Calculation of Frictional Force on an Inclined Plane

To determine the frictional force acting on a body sliding down an inclined plane, we need to consider the forces acting on the body and apply Newton's second law of motion.

The forces acting on the body are: 1. Weight (mg): The force due to gravity acting vertically downward, where m is the mass of the body and g is the acceleration due to gravity (approximately 9.8 m/s^2). 2. Normal force (N): The force exerted by the inclined plane perpendicular to its surface. It is equal in magnitude and opposite in direction to the component of the weight perpendicular to the plane. 3. Frictional force (f): The force opposing the motion of the body along the inclined plane.

The acceleration of the body down the inclined plane is given as 2 m/s^2.

To find the frictional force, we can use the following equation:

Net force = mass × acceleration

The net force acting on the body is the difference between the component of the weight parallel to the inclined plane and the frictional force:

Net force = m × g × sin(θ) - f

where θ is the angle of inclination of the plane (40 degrees in this case).

Since the body is sliding down the inclined plane, the frictional force opposes the motion and acts in the opposite direction to the component of the weight parallel to the plane. Therefore, the frictional force can be expressed as:

f = m × g × sin(θ) - m × a

Substituting the given values: - mass (m) = 10 kg - acceleration due to gravity (g) = 9.8 m/s^2 - angle of inclination (θ) = 40 degrees - acceleration (a) = 2 m/s^2

We can now calculate the frictional force:

f = (10 kg) × (9.8 m/s^2) × sin(40 degrees) - (10 kg) × (2 m/s^2)

Using a calculator, we find that the frictional force is approximately 47.6 N.

Please note that the diagram you mentioned is not visible in the text. However, the calculation provided above should help you determine the frictional force on the inclined plane.