Question

Площадь пластин плоского конденсатора ёмкостью 200 пФ равна 100 см2. Каким должно быть расстояние между пластинами конденсатора с такой ёмкостью, если в качестве диэлектрика использованы стеклянные пластины? Для стекла ε=7. Пожалуйста помогите решить, заранее спасибо.

Answer 1

дано

С=200 пФ=200*10^-12 Ф

S=100 см2=0.01 м2

εo=8.85*10-12 c4*A2 / м3*кг

ε=7.

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d - ?

 

решение

 

C =εεo *S/d

d= εεo *S/C = 7*8.85*10-12*0.01 /200*10^-12= 0.003 м = 3 мм

 

ответ 0.003 м = 0.3 см = 3 мм

Answer 2

Calculation of the Distance Between the Plates of a Capacitor

To calculate the distance between the plates of a capacitor with a capacitance of 200 pF and glass plates as the dielectric material (with ε = 7), we can use the formula for the capacitance of a parallel plate capacitor:

C = (ε * ε₀ * A) / d

Where: - C is the capacitance of the capacitor - ε is the relative permittivity (dielectric constant) of the material - ε₀ is the vacuum permittivity (ε₀ = 8.854 x 10⁻¹² F/m) - A is the area of the plates - d is the distance between the plates

We are given that the capacitance (C) is 200 pF and the area (A) is 100 cm².

Let's substitute the given values into the formula and solve for d:

200 pF = (7 * 8.854 x 10⁻¹² F/m * 100 cm²) / d

To simplify the calculation, we need to convert the area from cm² to m²:

A = 100 cm² = 100 x 10⁻⁴ m²

Substituting the values:

200 x 10⁻¹² F = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / d

Simplifying further:

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

Now, let's calculate the value of d using the given formula and the provided values:

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10⁻¹² F)

d = (7 * 8.854 x 10⁻¹² F/m * 100 x 10⁻⁴ m²) / (200 x 10