Question

Водород, находится в сосуде при температуре 20 Сº , нагревают до температуры 60 С º. Найдите давление воздуха после нагревания , если до нагревания оно было равно атмосферному .

Answer 1

Дано T1=293 К  T2=333 К   V = сonst     P2/P1  - ?
P1/T1 = P2/T2
P2 = P1*T2/T1=10^5*333/293=1,14*10^5 Па

Answer 2

Calculation of the Pressure Increase

To calculate the pressure of the air after heating the hydrogen in the vessel, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin

First, let's convert the temperatures from Celsius to Kelvin:

Initial temperature (T1) = 20°C = 20 + 273.15 = 293.15 K Final temperature (T2) = 60°C = 60 + 273.15 = 333.15 K

Since the volume and the number of moles of the gas remain constant, we can simplify the equation to:

P1/T1 = P2/T2

Where: - P1 is the initial pressure of the gas (atmospheric pressure) - P2 is the final pressure of the gas (unknown)

Now, let's substitute the values into the equation:

P1 = atmospheric pressure = 1 atm T1 = 293.15 K T2 = 333.15 K

1/293.15 = P2/333.15

To find P2, we can rearrange the equation:

P2 = (1/293.15) * 333.15

Calculating this expression gives us the final pressure of the air after heating the hydrogen in the vessel.

Calculation:

P2 = (1/293.15) * 333.15

P2 ≈ 1.135 atm

Therefore, the pressure of the air after heating the hydrogen in the vessel to 60°C is approximately 1.135 atm.