Question

Уклон длиной 100 м лыжник прошел за 20 секунд двигаясь с ускорением 0.4 м/с2.НАЙТИ НАЧАЛЬНУЮ И КОНЕНУЮ СКОРОСТЬ В НАЧАЛЕ И КОНЦЕ УКЛОНА!!!!!!!

Answer 1

Vo=0м/с
 теперь находим V конечную
S=$\frac{V ^{2 }-V ^{2}0 }{2a}$
V= $\sqrt{h*2a}$
V=8.9м/c

Answer 2

Calculation of Initial and Final Velocities

To find the initial and final velocities of the skier on a slope, we can use the equations of motion. Given the following information:

- Length of the slope (l) = 100 m - Time taken to traverse the slope (t) = 20 seconds - Acceleration (a) = 0.4 m/s^2

We can use the equation:

l = ut + (1/2)at^2

where: - l is the length of the slope - u is the initial velocity - t is the time taken - a is the acceleration

To find the initial velocity (u), we rearrange the equation:

u = (l - (1/2)at^2) / t

Substituting the given values:

u = (100 - (1/2)(0.4)(20^2)) / 20

Simplifying the equation:

u = (100 - 0.4 * 200) / 20

u = (100 - 80) / 20

u = 20 / 20

u = 1 m/s

Therefore, the initial velocity of the skier at the beginning of the slope is 1 m/s.

To find the final velocity (v), we can use the equation:

v = u + at

Substituting the given values:

v = 1 + (0.4)(20)

Simplifying the equation:

v = 1 + 8

v = 9 m/s

Therefore, the final velocity of the skier at the end of the slope is 9 m/s.

Please note that the calculations assume constant acceleration throughout the motion and neglect any other external factors that may affect the skier's velocity.