Question

4. Давление масла на большой поршень гидравлического пресса пло­щадью S= 500 см2 составляет p = 2000 кПа. Какая работа A соверша­ется при перемещении поршня на высоту h = 5 см?

Answer 1

A=F*h
F=P*S
A=P*S*h= 2*10^6 Па * 0,5 м^2 * 0,05м = 50000Дж

Answer 2

Calculation of Work Done by the Hydraulic Press

To calculate the work done by the hydraulic press when the piston is moved to a height of 5 cm, we need to use the formula:

Work (A) = Force (F) × Distance (d)

In this case, the force exerted by the oil on the large piston is equal to the pressure multiplied by the area of the piston:

Force (F) = Pressure (p) × Area (S)

Given that the pressure is 2000 kPa and the area of the piston is 500 cm², we can calculate the force:

F = 2000 kPa × 500 cm²

Now, let's convert the units to ensure consistency:

F = 2000 kPa × 500 cm² = 2000 N/m² × 0.05 m²

Simplifying the calculation:

F = 2000 N/m² × 0.05 m² = 100 N

The force exerted by the oil on the piston is 100 N.

Next, we need to calculate the distance the piston is moved, which is given as 5 cm. Converting this to meters:

Distance (d) = 5 cm = 0.05 m

Now, we can calculate the work done:

Work (A) = Force (F) × Distance (d) = 100 N × 0.05 m

Simplifying the calculation:

Work (A) = 100 N × 0.05 m = 5 J

Therefore, the work done by the hydraulic press when the piston is moved to a height of 5 cm is 5 Joules.